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Exit Shellcode x86

Exit in Assembly :
For writing exit assembly program we need to check exit syscall reference number .
I use this online man page :
https://syscalls.kernelgrok.com/


From above we can conclude that for exit system call we need 2 registers :
[x] EAX => Eax should contain exit sys call number (0x01)
[x] EBX => Ebx should contain  error code (0 for normal exit)

A good shell-code :
[x] Should be Null free
[x] Smaller in length
[x] Position Independent

Below is my code :


I wrote a small script to compile and assemble nasm program and extract the shellcode from it then saving the shellcode into a c file and compiling the new c program.
Here is my script :



Tweaked some instructions :p


Next you can debug and check the execution in gdb by setting breakpoints and stepping instructions one by one .
Below is my gdb console before calling interrupt int 0x80 showing the value of eax and ebx as expected :)

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Comments

  1. www.vardanbansal/blogApril 2, 2018 at 10:33 AM

    great... 👌🙏

    ReplyDelete
  2. UnknownApril 2, 2018 at 11:06 AM

    Nice !!!!

    ReplyDelete
  3. KennethApril 16, 2021 at 6:16 AM

    Shellcode Length: 8
    --- SIGSEGV {si_signo=SIGSEGV, si_code=SEGV_ACCERR, si_addr=0x555555558038} ---
    +++ killed by SIGSEGV +++
    zsh: segmentation fault strace -e exit ./shellcode

    ReplyDelete

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